\(\left(x-12+y\right)^2+\left(y+4-x\right)^2=0\)
\(\Rightarrow\left(x-12+y\right)^2=0\) và \(\left(y+4-x\right)^2=0\)
+) \(\left(x-12+y\right)^2=0\Rightarrow x-12+y=0\)
\(\Rightarrow x+y=12\)
+) \(\left(y+4-x\right)^2=0\Rightarrow y+4-x=0\Rightarrow y-x=-4\)
\(\Rightarrow x=\left(12+4\right):2=8\)
\(\Rightarrow y=\left(12-4\right):2=4\)
Vậy \(x=8;y=4\)
Tìm x, y, zϵ R biết: \(\left(4x^2-4x+1\right)^{2022}+\left(y^2-\dfrac{4}{5}y+\dfrac{4}{25}\right)^{2022}+\left|x+y-z\right|=0\)
Tìm x,y,z biết: \(\left|x-\frac{1}{2}\right|+\left|y+\frac{2}{3}\right|+\left|x^2+xz\right|=0\)
tìm x,y biết
x+\(\left(\dfrac{-31}{12}\right)^2\)=\(\left(\dfrac{49}{12}\right)^2\)-x=y\(^{^{ }2}\)
\(\left(\dfrac{1}{2}.x-5\right)^{20}+\left(y^2-\dfrac{1}{4}\right)^{10}\)\(\le\)0
Tìm x, y biết :
\(\left|x+3\right|+\left|x-1\right|=\dfrac{16}{\left|y-2\right|+\left|y+2\right|}\)
Tìm x,y biết:
a)\(\left|x-\dfrac{4}{11}\right|+\left|5+y\right|=0\)
b)\(\left|\dfrac{1}{2}-\dfrac{1}{3}+x\right|=\dfrac{-1}{4}-\left|y\right|\)
c)\(\left|x-y\right|+\left|\dfrac{9}{25}+y\right|=0\)
Tìm x;y biết :
\(\dfrac{6}{\left(x-1\right)^2+2}=\left|y-1\right|+\left|y-2\right|+\left|y-3\right|+1\)
Tìm x, y biết :
\(\left(x+y-2\right)^2+7=\dfrac{14}{\left|y-1\right|+\left|y-3\right|}\)
a/tìm x biết:
5\(|\frac{3}{4}-\frac{2}{3}x|-3,25=-2\left\{\left(1,25\right)^2-2,5.0,25+\left(0,25\right)^2\right\}\)
b/timd x,y biết:\(\left|3+y\right|+\left|2x+y\right|=0\)
Tìm x, y ϵ Z, biết :
\(\left(x+2\right)^2+4=\dfrac{20}{3\left|y+2\right|+5}\)
