Ta có:
\(3x^2-6x+4y^2-4xy+4y+3=0\)
\(\Leftrightarrow x^2-4xy+4y^2-2x+4y+1+2x^2-4x+2=0\)
\(\Leftrightarrow\left(x-2y\right)^2-2\left(x-2y\right)+1+2\left(x^2-2x+1\right)=0\)
\(\Leftrightarrow\left(x-2y-1\right)^2+2\left(x-1\right)^2=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x-2y-1=0\\x-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=0\end{matrix}\right.\)
Vậy ...
Giải hệ phương trình: \(\left\{{}\begin{matrix}x^5-x^4y+x-y=0\left(1\right)\\x^3-3x^2y+4xy^2-4y^3=54\left(2\right)\end{matrix}\right.\)
Giai pt nghiem nguyen
a)\(x^2-6x+y^2+10y=24\)
b)\(x^2-3x+y^2-6y+10=0\)
c)\(\left(x+y+1\right)^2=3\left(x^2+y^2+1\right)\)
d)\(x^2+5y^2-4xy-4y+4=0\)
\(\left\{{}\begin{matrix}x^2-4xy+x+2y=0\\x^4-8x^2y+3x^2+4y^2=0\end{matrix}\right.\)
Tìm \(x,y\in Z\) thỏa mãn \(x^2+5y^2-4xy-4y+3=0\)
\(\left\{{}\begin{matrix}x^2-4xy+4z^2+12=0\\y^2-4yz+x^2-12=0\\16x^2-8xz+4y^2=0\end{matrix}\right.\)
Giải hệ \(\left\{{}\begin{matrix}\left(x+4y\right)\left(x^2+16y^2\right)=32xy\left(x+4y-3\sqrt{xy}\right)\\\sqrt{3x-1}+6x=\sqrt{8y+3}+8\left(2y+1\right)\end{matrix}\right.\)
giải hệ phương trình
\(\left\{{}\begin{matrix}x^4-x^3+3x^2-4y-1=0\\\sqrt{\dfrac{x^2+4y^2}{2}}+\sqrt{\dfrac{x^2+2xy+4y^2}{3}}=x+2y\end{matrix}\right.\)
Giaỉ hệ phương trình
1) \(\left\{{}\begin{matrix}x^2-2xy+x+y=0\\x^4-x^2\left(4y-3\right)+y^2=0\end{matrix}\right.\)
2)\(\left\{{}\begin{matrix}3x^2+2xy+y^2=11\\x^2+2xy+3y^2=17\end{matrix}\right.\)
3)\(\left\{{}\begin{matrix}x^3-2y^3-x-4y=0\\13x^2-41xy+21y^2+9=0\end{matrix}\right.\)
tìm nghiệm nguyên của phương trình x2 + 5y2 - 4xy + 4x - 4y + 3 = 0
