\(x=\sqrt{x}\) ( ĐK ; x dương )
\(\Rightarrow x-\sqrt{x}=0\)
\(\Rightarrow\sqrt{x}.\left(\sqrt{x}-1\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}\sqrt{x}=0\\\sqrt{x}-1=0\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\x=\pm1\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\x=1\end{array}\right.\)
Vậy x = 0 ; x = 1