p) Để \(\begin{cases}70⋮x\\80⋮x\end{cases}\)
<=> x \(\in\) ƯC(70;80)
Ta có : 70 = 2 . 5 . 7
80 = 24 . 5
=> ƯCLN(70;80) = 2 . 5 = 10
=> ƯC(70;80) = Ư(10) = { - 10 ; - 5 ; - 2 ; - 1 ; 1 ; 2 ; 5 ; 10 }
Vì x > 8
=> x \(\in\) { 10 }
q) Để \(\begin{cases}x⋮12\\x⋮25\\x⋮30\end{cases}\)
<=> x \(\in\) BC(12;25;30)
Ta có : 12 = 22 . 3
25 = 52
30 = 2 . 3 . 5
=> BCNN(12;25;30) = 22 . 52 . 3 = 300
=> BC(12;25;30) = B(300) = { 0 ; 300 ; 600 ; ... }
Vì 0 < x < 500
=> x \(\in\) { 300 }
\(70⋮x,80⋮x\Rightarrow x\inƯC\left(70;80\right)=\left\{\pm1;\pm2;\pm5;\pm10\right\}\)
Vì x > 8 nên \(x=10\)
\(x⋮12,x⋮25,x⋮30\Rightarrow x\in BC\left(12;25;30\right)=\left\{0;\pm300;\pm600;...\right\}\)
Vì \(0< x< 500\) nên \(x=300\)