x2 - \(\frac{3}{5}\) /x/ = 0
=> x2 = \(\frac{3}{5}\) /x/
=> x . x = \(\frac{3}{5}\) . /x/
2TH
TH1: /x/ = x => x = \(\frac{3}{5}\)
TH2: /x/ \(\ne\) x => x = -\(\frac{3}{5}\)
mn ơi giúp mk vs ak
tìm x biết :
\(\left|x-1\right|+2.\left|x-2\right|+3.\left|x-3\right|+4.\left|x-4\right|+5.\left|x-5\right|+20x=0\)
Tìm x,y,z biết: \(\left|x-\frac{1}{2}\right|+\left|y+\frac{2}{3}\right|+\left|x^2+xz\right|=0\)
a/tìm x biết:
5\(|\frac{3}{4}-\frac{2}{3}x|-3,25=-2\left\{\left(1,25\right)^2-2,5.0,25+\left(0,25\right)^2\right\}\)
b/timd x,y biết:\(\left|3+y\right|+\left|2x+y\right|=0\)
Bài 1: Tìm x biết: \(\left|x-3\right|+\left|x+2\right|=7\)
Bài 2: CMR: \(\frac{1}{4}+\frac{1}{4^2}+\frac{1}{4^3}+...+\frac{1}{4^{999}}+\frac{1}{4^{1000}}< \frac{1}{3}\)
Bài 3: Tìm x biết:
a) \(x\left(x-2\right)\left(x-3\right)>0\)
b) \(x\left(x-2\right)\left(x-3\right)< 0\)
Tìm \(x,\) biết:
a) \(4\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
b) \(3\left|x+4\right|-\left|2x+1\right|-5\left|x+3\right|+\left|x+9\right|=5\)
c) \( \left|2\frac{1}{5}-x\right|+\left|x-\frac{1}{5}\right|+8\frac{1}{5}=1,2\)
d) \(2\left|x+3\frac{1}{2}\right|+\left|x\right|-3\frac{1}{2}=\left|2\frac{1}{5}-x\right|\)
a) tìm x, y, z biết:
\(\left(x-\frac{1}{5}\right).\left(y+\frac{1}{2}\right).\left(z-3\right)=0\)và \(x+1=y+2=z+3\)
b) Tìm x biết \(|x^2+|x-1||=x^2+2\)
Bài 1: Tìm x biết:
a, \(x.\cdot\left(\frac{1}{4}+\frac{1}{5}\right)-\left(\frac{1}{7}+\frac{1}{8}\right)=0\)
b, \(\left(5x-1\right).\left(2x-\frac{1}{3}\right)=0\)
c, \(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
d, \(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
e, \(\frac{-3}{4}-\left|\frac{4}{5}-x\right|=-1\)
Tìm x biết :
\(\left(x^2-20\right)\left(x^2-15\right)\left(x^2-10\right)\left(x^2-5\right)< 0\)
bài 1 :tính bằng cách hợp lí nhất : a) \(\frac{4}{5}\left(\frac{7}{2}+\frac{1}{4}\right)^2\)
b) \(\frac{5^4.20^4}{25^5.4^5}\)
bài 2 : tìm x và y biết x:2 = y: (-5) và x-y =10
bài 3 tìm x,y,z biết \(\left(x-\frac{1}{5}\right)^{2004}+\left(y+0,4\right)^{100}+\left(z-3\right)^{678}=0\)
