Question

tìm x,biết

\(\left|x+\dfrac{3}{5}\right|-\dfrac{1}{2}=\dfrac{1}{2}\)

Answer 1

\(\left|x+\dfrac{3}{5}\right|-\dfrac{1}{2}=\dfrac{1}{2}\)

\(\Leftrightarrow\left|x+\dfrac{3}{5}\right|=\dfrac{1}{2}+\dfrac{1}{2}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{3}{5}=1\\x+\dfrac{3}{5}=-1\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=1-\dfrac{3}{5}\\x=-1-\dfrac{3}{5}\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{8}{5}\end{matrix}\right.\)

Vậy \(\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{8}{5}\end{matrix}\right.\)