Question

Tìm \(x\),biết :

\(2x\left(x-5\right)-x\left(3+2x\right)=26\)

Answer 1

Ta có: \(2x\left(x-5\right)-x\left(3+2x\right)=26\\ < =>2x^2-10x-3x-2x^2=26\\ < =>-13x=26\\ =>x=\dfrac{26}{-13}=-2\)

Answer 2

2x (x - 5) - x (3 + 2x) = 26

\(\Leftrightarrow\) 2x² - 10x - 3x - 2x² = 26

\(\Rightarrow\) -13x = 26

\(\Rightarrow\) x = -2

Vậy x = -2

Answer 3

\(2x\left(x-5\right)-x\left(3+2x\right)=26\)

\(\Leftrightarrow\) \(x\left[2\left(x-5\right)-\left(3+2x\right)\right]=26\)

\(\Leftrightarrow\) \(x\left(2x-10-3-2x\right)=26\)

\(\Leftrightarrow\) \(x\left(-13\right)=26\)

\(\Leftrightarrow\) \(x=\dfrac{-26}{13}\)

\(\Leftrightarrow\) \(x=-2\)

Answer 4

<=>2x²-10x-3x-2x²=26

<=>-13x=26

<=>x=26:(-13)

<=>x=-2

vay. x=-2