Question

tìm x

a/ (x-1/4)⁴=1/256

b/ (3x-2)⁵ = -234

c/ x¹³= 27 X x¹⁰

d/ (4x-1)²= (1-4x)⁴

Answer 1

a ) \(\left(x-\frac{1}{4}\right)^4=\frac{1}{256}\)

      \(\left(x-\frac{1}{4}\right)=\sqrt[4]{\frac{1}{256}}\)

      \(\left(x-\frac{1}{4}\right)=\frac{1}{4}\)

           \(x=\frac{1}{4}+\frac{1}{4}\)

            \(x=\frac{1}{2}\)

b ) \(\left(3x-2\right)^5=-234\)

      \(\left(3x-2\right)=-\sqrt[5]{234}\)

      \(\left(3x-2\right)=-2,977441049\)

        \(3x=-0,9774410485\)

          \(x=-0,3258136828\)

 

Answer 2

a.

(x-1/4)^4=1/256

(x-1/4)^4=(1/4)^4

x-1/4=1/4

x=1/4+1/4

x=2/4