n: \(\left(x^2+x\right)\left(x^2+x+1\right)=6\)
=>\(\left(x^2+x\right)^2+\left(x^2+x\right)-6=0\)
=>\(\left(x^2+x+3\right)\left(x^2+x-2\right)=0\)
=>\(x^2+x-2=0\)
=>(x+2)(x-1)=0
=>\(\left[\begin{array}{l}x+2=0\\ x-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=-2\\ x=1\end{array}\right.\)
p: \(\left(x-1\right)^3+\left(2-x\right)\left(4+2x+x^2\right)+3x\left(x+2\right)=17\)
=>\(x^3-3x^2+3x-1+8-x^3+3x^2+6x=17\)
=>9x+7=17
=>9x=10
=>\(x=\frac{10}{9}\)
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