Ta có \(\frac{x}{-3}=\frac{x}{3};\frac{y}{-14}=\frac{y}{14}\)
Đặt \(\frac{-x}{3}=\frac{y}{7}=\frac{-x}{3}.\frac{1}{2}=\frac{-x}{6}\)
\(\frac{y}{7}.\frac{1}{2}=\frac{y}{14}\)
Đặt \(\frac{-y}{14}=\frac{z}{5}=\frac{-y}{14}.\frac{1}{1}=\frac{-y}{14}\)
\(\frac{z}{5}.\frac{1}{1}=\frac{z}{5}\)
⇒ \(\frac{-x}{6}=\frac{y}{14}=\frac{z}{5}\)
Đặt \(\frac{-x}{6}=\frac{y}{14}=\frac{z}{5}=k\)
⇒ -x = -6k ; y= 14k ; z = 5k
Thay -x= -6k ; y = 14k ;z = 5k vào 2k + 4y - 6z = 15
⇒ - 6.2k + 14.4k - 5.6k = 15
-12k + 56k - 30k = 15
14k = 15
k = \(\frac{15}{14}\)
Vậy x = \(\frac{15}{14}.-6=\frac{-45}{7}\)
y = \(\frac{15}{14}.14=15\)
z = \(\frac{15}{14}.5=\frac{75}{14}\)
Vậy x = y = z =
