\(xy-3x-y+3=23\)
\(\Rightarrow x\left(y-3\right)-\left(y-3\right)=23\)
\(\Rightarrow\left(y-3\right)\left(x-1\right)=23\)
Ta có bảng sau:
y - 3 | 23 | -23 | 1 | -1 |
x - 1 | 1 | -1 | 23 | -23 |
y | 26 | -20 | 4 | 2 |
x | 2 | 0 | 24 | -22 |
Vậy \(\left(x,y\right)\in\left\{\left(2;26\right);\left(0;-20\right);\left(24;4\right);\left(-22;2\right)\right\}\).