Question

Tìm x

 x+ ( x+1 ) + x+2 ) + ... + ( x+ 2003) = 2004

Answer 1

x+(x+1)+(x+2)+...+(x+2003)=2004

2004x+1+2+3+...+2003=2004

2004x+ \(\frac{2003.\left(1+2003\right)}{2}\) = 2004

2004x= 2004-2007006

2004x= -2005002

x= -20052002:2004= -1000,5

Vậy x=-1000,5

Answer 2

x + (x + 1) + (x + 2) + ... + (x + 2003) = 2004

=> 2004x + 1 + 2 + 3 + ... + 2003 = 2004

=> 2004x + \(\frac{\left(1+2003\right)\cdot2003}{2}\) = 2004

=> 2004x + 2007006 = 2004

=> 2004x = -2005002

=> x = -2005002 : 2004 = \(-1000\frac{1}{2}\)