Ta có: \(\left(x-3\right)\left(x^2+3x+9\right)+x\left(2+x\right)\left(2-x\right)=0\)
\(\Leftrightarrow x^3-27+x\left(4-x^2\right)=0\)
\(\Leftrightarrow4x-27=0\)
\(\Leftrightarrow4x=27\)
hay \(x=\dfrac{27}{4}\)
Tìm x , biết :
a. \(\left(x-2\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+6\left(x+1\right)^2=15\)
b. \(2x^3-50x=0\)
c.\(5x^2-4\left(x^2-2x+1\right)-5=0\)
d. \(x^3-x=0\)
e. \(27x^3-27x^2+9x-1=1\)
Tìm x biết:
d) (x-2)3-(x-3).(x2+3x+9)+6.(x+1)2=15
e) (x-1)3+(2-x).(4+2x+x2)+3x.(x+2)=17
f) (3x+3)2-18x=36+(x-3).(x2+3x+9)
Giải chi tiết giúp mình nha.Cảm ơn.
TÌM X
(2x-3)^2-4x-9=0
(3x-7).(3x+7)-54x-9x^2=0
(x+8)^2-x^2= 24
(x-2).(x^2+2x+4)+8-4x= 0
Em cảm ơn ạ
Tìm x biết:
a) (x-3).(x2+3x+9) + (x+2).(2-x) = 1
b) x3-8-(x-2).(x2+3) = 0
c) (2x+1)3-(x-2)3 = 0
Tìm x biết:
\(\left(x-1\right)^3-\left(x+3\right)\left(x^2-3x+9\right)+3\left(x^2-4\right)=2\)
tìm x
b) (x + 3)2 - (x - 4)( x + 8) = 1;
c) 3(x + 2)2 + (2x - 1)2 - 7(x + 3)(x - 3) = 36;
d)(x - 3)(x2 + 3x + 9) + x(x + 2)(2 - x) = 1;
e) (x + 1)3 - (x - 1)3 - 6(x - 1)2 = -19.
hihi
Bài 1:Tìm x,biết:
a,(x-2)(x+2)-(x-3)\(^2\)=9
b,(x-1)(x\(^2\)+1)-(x+1)(x\(^2\)-x+1)=x(2-x)
c,(x-3)(x\(^2\)+3x+9)+x(x+2)(2-x)=1
d,(x+1)\(^3\)-(x-1)\(^{^{ }3}\)-6(x-1)\(^2\)=-19
Bài 2:Viết về dạng bình phương hoặc dạng tích:
a,\(\dfrac{1}{27}\)x\(^3\)+x\(^2\)+9x+27
b,8u\(^3\)-60u\(^2\)v+150uv\(^2\)-125v\(^3\)
c,x^3+3x^2+3x+1+3(x^2+2x+1)y+3xy^2+3y^3+y^3
(3x-2)(3x+2)-9(x-1).x=0
tìm x
a)(x+3)(x2-3x+9)-x3=2x
b)(x-2)3-(x-3)(x2+3x+9)+6(x+1)2=15
