Lời giải:
PT \(\Leftrightarrow x^2-x(2a+1)-(3a^2-11a+6)=0\)
\(\Delta=(2a+1)^2+4(3a^2-11a+6)=16a^2-40a+25\)
\(=(4a-5)^2\)
Khi đó:
\(x=\frac{-b\pm \sqrt{\Delta}}{2a}=\left[\begin{matrix} \frac{2a+1+4a-5}{2}=3a-2\\ \frac{2a+1+5-4a}{2}=3-a\end{matrix}\right.\)