\(\sqrt{49\left(x-3\right)^2}-10=48\)
\(\rightarrow7\left(x-3\right)=58\)
\(\rightarrow x-3=\frac{58}{7}\)
\(\Rightarrow x=\frac{79}{7}\)
Tìm x:
49(x−3)2 \(\sqrt{49(x−3)^2} \)- 10 = 48
\(\Leftrightarrow\) \(\sqrt{49} . \sqrt{(x-3)^2} = 58\)
\(\Leftrightarrow\) \(7 . | x-3| = 58 \)
\(\Leftrightarrow\) \(| x-3| = \dfrac{58}{7}\)
* \(x-3 \) = \(\dfrac{58}{7} \)
\(\Leftrightarrow\) \(x= \dfrac{79}{7} \)
* \(-x-3=\dfrac{58}{7}\)
\(\Leftrightarrow\) \(-x= \dfrac{79}{7}\)
\(\Leftrightarrow\) \(x = \dfrac{-79}{7}\)
Vậy \(x = \dfrac{79}{7} \) hoặc \(x = \dfrac{-79}{7}\)
