Question

tìm x min:A=/x/+/8-x/

Answer 1

\(A=\left|x\right|+\left|8-x\right|\)

Áp dụng bđt:

\(\left|a\right|+\left|b\right|\ge\left|a+b\right|\)

\(A\ge\left|x+8-x\right|\)

\(A\ge8\)

Dấu "=" xảy ra khi:

\(\left[{}\begin{matrix}\left\{{}\begin{matrix}x\ge0\\8-x\ge0\Rightarrow x\le8\end{matrix}\right.\\\left\{{}\begin{matrix}x< 0\\8-x< 0\Rightarrow x>8\end{matrix}\right.\end{matrix}\right.\)

\(\Rightarrow0\le x\le8\)