Question

Tìm x:

\(\left(x-3\right)^5=\left(x-3\right)^7\)

Answer 1

\(\left(x-3\right)^5=\left(x-3\right)^7\)

\(\Rightarrow\left(x-3\right)^7-\left(x-3\right)^5=0\)

\(\Rightarrow\left(x-3\right)^5\left[\left(x-3\right)^2-1\right]=0\)

\(\Rightarrow\left[{}\begin{matrix}\left(x-3\right)^5=0\\\left(x-3\right)^2-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\\left(x-3\right)^2=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\\left[{}\begin{matrix}x=4\\x=2\end{matrix}\right.\end{matrix}\right.\)

Vậy x = 2; x = 3; x = 4