Question

tìm x \(\dfrac{1-\dfrac{1}{2}+\dfrac{x}{1-\dfrac{1}{2}}}{1+\dfrac{1}{2}-\dfrac{1}{1+\dfrac{1}{2}}}=\dfrac{7}{5}\)

Answer 1

\(\dfrac{1-\dfrac{1}{2}+\dfrac{x}{1-\dfrac{1}{2}}}{1+\dfrac{1}{2}-\dfrac{1}{1+\dfrac{1}{2}}}=\dfrac{7}{5}\Rightarrow\dfrac{\dfrac{1}{2}+\dfrac{x}{\dfrac{1}{2}}}{\dfrac{3}{2}-\dfrac{1}{\dfrac{3}{2}}}=\dfrac{7}{5}\)

\(\Rightarrow\dfrac{\dfrac{1}{2}+2x}{\dfrac{3}{2}-\dfrac{3}{2}}=\dfrac{7}{5}\Rightarrow\dfrac{\dfrac{1}{2}+2x}{0}=\dfrac{7}{5}\Rightarrow\dfrac{1}{2}+2x=0\)

\(\Rightarrow2x=-\dfrac{1}{2}\Rightarrow x=-\dfrac{1}{4}\)

Vậy \(x=-\dfrac{1}{4}\)