a: \(\Leftrightarrow2x^2-x+\dfrac{1}{3}-\dfrac{2}{3}x=0\)
\(\Leftrightarrow2x^2-\dfrac{5}{3}x+\dfrac{1}{3}=0\)
\(\Leftrightarrow6x^2-5x+1=0\)
\(\Leftrightarrow6x^2-2x-3x+1=0\)
=>(2x-1)(3x-1)=0
=>x=1/3 hoặc x=1/2
b: \(\Leftrightarrow x\left(x-4\right)+\left(x-4\right)^2=0\)
=>(x-4)(2x-4)=0
=>x=4 hoặc x=2