\(\dfrac{x+3}{x+5}=\dfrac{x-2}{x-7}\)
\(\Rightarrow\left(x+3\right)\left(x-7\right)=\left(x+5\right)\left(x-2\right)\)
\(\Rightarrow x^2+3x-7x-21=x^2+5x-2x-10\)
\(\Rightarrow x^2-4x-21=x^2+3x-10\)
\(\Rightarrow-4x-21=3x-10\)
\(\Rightarrow-4x-3x=-10+21\)
\(\Rightarrow-7x=11\)
\(\Rightarrow x=-\dfrac{11}{7}\)
Vậy \(x=-\dfrac{11}{7}\)