\(\left|\frac{3}{4}x-\frac{3}{40}\right|-\frac{3}{4}=\left|-\frac{3}{4}\right|\)
\(\Leftrightarrow\left|\frac{3}{4}x-\frac{3}{4}\right|-\frac{3}{4}=\frac{3}{4}\)
\(\Leftrightarrow\left|\frac{3}{4}x-\frac{3}{4}\right|=\frac{3}{4}+\frac{3}{4}\)
\(\Leftrightarrow\left|\frac{3}{4}x-\frac{3}{4}\right|=\frac{3}{2}\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}\frac{3}{4}x-\frac{3}{4}=\frac{3}{2}\\3x-\frac{3}{4}=-\frac{3}{2}\end{array}\right.\Leftrightarrow\left[\begin{array}{nghiempt}3x=\frac{9}{4}\\3x=-\frac{3}{4}\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{3}{4}\\x=-\frac{1}{4}\end{array}\right.\)
Vậy ........................
\(\left|\frac{3}{4}x-\frac{3}{4}\right|-\frac{3}{4}=\left|-\frac{3}{4}\right|\)
\(\Rightarrow\left|\frac{3}{4}x-\frac{3}{4}\right|-\frac{3}{4}=\frac{3}{4}\)
\(\Rightarrow\left|\frac{3}{4}x-\frac{3}{4}\right|=\frac{3}{4}+\frac{3}{4}\)
\(\Rightarrow\left|\frac{3}{4}x-\frac{3}{4}\right|=\frac{3}{2}\)
\(\Rightarrow\left|\frac{3}{4}.\left(x-1\right)\right|=\frac{3}{2}\)
\(\Rightarrow\left|\frac{3}{4}\right|.\left|x-1\right|=\frac{3}{2}\)
\(\Rightarrow\left|x-1\right|=\frac{3}{2}:\frac{3}{4}\)
\(\Rightarrow\left|x-1\right|=\frac{3}{2}.\frac{4}{3}=2\)
\(\Rightarrow\left[\begin{array}{nghiempt}x-1=2\\x-1=-2\end{array}\right.\) \(\Rightarrow\left[\begin{array}{nghiempt}x=3\\x=-1\end{array}\right.\)
Vậy \(\left[\begin{array}{nghiempt}x=3\\x=-1\end{array}\right.\)
Tuấn Anh Phan Nguyễn thử lại coi thử dúng k
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