\(\left(x^2+x+2\right)^2=16=4^2\Rightarrow\left[\begin{matrix}x^2+x+2=-4\left(1\right)\\x^2+x+2=4\left(2\right)\end{matrix}\right.\)
\(\left(1\right)\Leftrightarrow x^2+2.\frac{1}{2}x+\left(\frac{1}{2}\right)^2=-4-2+\frac{1}{4}=-\frac{23}{4}< 0\Rightarrow vôN_0\)
(2)\(\Leftrightarrow\left(x+\frac{1}{2}\right)^2=4-2+\frac{1}{4}=\frac{9}{4}=\left(\frac{3}{2}\right)^{^2}\Rightarrow\left[\begin{matrix}x=\frac{-1-3}{2}=-2\\x=\frac{-1+3}{2}=1\end{matrix}\right.\)
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