\(x+\left(2x-8\right)=17\)
\(\Rightarrow\left(x+2x\right)-8=17\)
\(\Rightarrow3x=25\)
\(\Rightarrow x=\frac{25}{3}\)
Vậy \(x=\frac{25}{3}\)
x + ( 2x - 8) = 17
( x + 2x ) - 8 = 17
( x + 2x ) = 17 + 8
( x + 2x ) = 25
=> x = \(\frac{25}{3}\)
\(x+\left(2x-8\right)=17\)
\(x+2x-8=17\)
\(x+2x=17+8\)
\(3x=25\)
\(x=\frac{25}{3}\)