Giải:
\(\left(x+2\right)^2=16\)
\(\left(x+2\right)^2=4^2\)
Vì \(2=2\)
Nên \(x+2=4\)
\(\Leftrightarrow x=4-2\)
\(\Leftrightarrow x=2\)
Vậy \(x=2\).
Chúc bạn học tốt!
\(\left(x+2\right)^2=16\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(x+2\right)^2=4^2\\\left(x+2\right)^2=\left(-4\right)^2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=4\\x+2=-4\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-6\end{matrix}\right.\)
Vậy ..
(x+2)2=16
=>(x+2)2=42
<=>x+2=4
=>x=4-2
=>x=2
:
