Question

tim x , biet: \(\sqrt{x^2}\)|x+2|=x

Answer 1

Ta có : \(\sqrt{x^2=x}\)

Thay vào phép toán , ta có :

\(x\cdot\left|x+2\right|=x\)

⇔\(\left|x+2\right|=1\)

\(\Rightarrow\left\{{}\begin{matrix}x+2=1\\x+2=-1\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-1\\x=-3\end{matrix}\right.\)

⇒\(x\in\left\{-1;-3\right\}\)

Vay ............