\(\sqrt{10+\sqrt{3x}}=2+\sqrt{6}\) (ĐKXĐ: x \(\ge\) 0)
\(\Leftrightarrow\) \(10+\sqrt{3x}=4+4\sqrt{6}+6\)
\(\Leftrightarrow\) \(10+\sqrt{3x}=10+4\sqrt{6}\)
\(\Leftrightarrow\) \(\sqrt{3x}=4\sqrt{6}\)
\(\Leftrightarrow\) \(3x=96\)
\(\Leftrightarrow\) \(x=32\) (TM)
Vậy x = 32
Chúc bn học tốt!