Ta có: \(\left(1-3x\right)^3=\left(-4\right)^3\)
Suy ra \(1-3x=-4\) nên \(x=\dfrac{5}{3}\)
Vậy x = \(\dfrac{5}{3}\)
\(\left(1-3x\right)^3=-64\)
\(\left(1-3x\right)^3=\left(-4\right)^3\)
\(1-3x=-4\)
\(3x=1-\left(-4\right)\)
\(3x=5\)
\(x=\dfrac{5}{3}\)
Vậy \(x=\dfrac{5}{3}\)