\(\left|2x-1\right|-3x=\dfrac{1}{2}\)
<=> \(\left[{}\begin{matrix}2x-1-3x=\dfrac{1}{2}\left(ĐK:x\ge\dfrac{1}{2}\right)\\-2x+1-3x=\dfrac{1}{2}\left(ĐK:x< \dfrac{1}{2}\right)\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}x=-\dfrac{3}{2}\left(loại\right)\\x=\dfrac{1}{10}\left(TM\right)\end{matrix}\right.\)