\(\frac{2x+1}{-3}=\frac{-7}{11}\)
\(\Leftrightarrow11\left(2x+1\right)=\left(-3\right).\left(-7\right)\)
\(\Leftrightarrow2x+1=\frac{21}{11}\)
\(\Leftrightarrow2x=\frac{21}{11}-1\)
\(\Leftrightarrow2x=\frac{10}{11}\)
\(\Leftrightarrow x=\frac{5}{11}\)
Vậy..