Question

Tìm x, biết

a.\(\dfrac{2}{3}\)x-\(\dfrac{1}{2}\)x = (\(\dfrac{-7}{12}\)) . \(\dfrac{7}{5}\)

b.(\(\dfrac{1}{5}\) - \(\dfrac{3}{2}\)x)\(^2\) = \(\dfrac{9}{4}\)

c. (1,25 - \(\dfrac{4}{5}\)x)\(^3\) = -125

d. 2\(^x\) + 2\(^{x+4}\) = 544

e.\(\dfrac{3}{4}\)x - 4,5+ \(\dfrac{4}{5}\)x = 3

g. \(\left|3x-2\right|\) =\(\left|2x-3\right|\)

h.(x² -4)\(\sqrt{x}\) = 0

i. (\(\dfrac{1}{3}\)x - 4 )² = \(\dfrac{16}{25}\)

j.4x² -1 = 0

k.2x²+0,82 =1

l.\(\dfrac{5}{12}\)\(\sqrt{x}\) - \(\dfrac{1}{6}\) = \(\dfrac{1}{3}\)

m.(\(\sqrt{x-1}\) + 5)(x-6\(\sqrt{x}\) = 0

Answer 1

a: =>1/6x=-49/60

=>x=-49/60:1/6=-49/60*6=-49/10

b: =>3/2x-1/5=3/2 hoặc 3/2x-1/5=-3/2

=>x=17/15 hoặc x=-13/15

c: =>1,25-4/5x=-5

=>4/5x=1,25+5=6,25

=>x=125/16

d: =>2^x*17=544

=>2^x=32

=>x=5

i: =>1/3x-4=4/5 hoặc 1/3x-4=-4/5

=>1/3x=4,8 hoặc 1/3x=-0,8+4=3,2

=>x=14,4 hoặc x=9,6

j: =>(2x-1)(2x+1)=0

=>x=1/2 hoặc x=-1/2