a) \(x^3-0,25x=0\\ < =>x\left(x^2-0,25\right)=0\\ =>\left[{}\begin{matrix}x=0\\x^2-0,25=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=0\\x=\sqrt{0,25}\end{matrix}\right.\)
b) \(x^2-10x=-25\\ < =>x^2-10x+25=0\\ < =>\left(x-5\right)^2=0\\ < =>x-5=0\\=>x=5\)
a) \(x^3-0,25x=0\)
\(x\left(x^2-0,25\right)=0\)
\(\Leftrightarrow x=0\) hoặc \(x^2-0,25=0\)
\(\Leftrightarrow x=0\) hoặc \(x=0,25\) hoặc \(x=-0,25\)
b) \(x^2-10x=-25\)
\(\Leftrightarrow x\left(x-10\right)=-25\)
\(\Leftrightarrow x=-25\) hoặc \(\Leftrightarrow x-10=-25\)
\(\Leftrightarrow x=-25\) hoặc x=-15
a, \(x^3-0,25x=0\)
\(x\left(x^2-0,25\right)=0\)
\(x\left(x-0,5\right)\left(x+0,5\right)=0\)
=> \(\left[{}\begin{matrix}x=0\\x-0,5=0\\x+0,5=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\\x=0,5\\x=\left(-0,5\right)\end{matrix}\right.\)
b,\(x^2-10x=-25\)
x(x-10)=(-25)
\(\left[{}\begin{matrix}x=0\\x-10=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\\x=10\end{matrix}\right.\)
b,\(x^2-10x=-25\)
=> \(x^2-2.x.5+5^2=0\)
=> \(\left(x-5\right)^2=0=>x-5=0=>x=5\)