b)\(\left|x-3\right|=x-3\)
*Nếu \(x-3\ge0\Rightarrow x\ge3\)
\(x-3=x-3\)
\(x-x=-3+3\)
\(0x=0\)
\(x\in R\)(trừ ĐK \(x\ge3\))
*Nếu \(x-3< 0\Rightarrow x< 3\)
\(-\left(x-3\right)=x-3\)
\(3-x=x-3\)
\(-x-x=-3-3\)
\(-2x=-6\)
\(x=3\)
a) \(\left|x-1\right|=1-x\)
* \(x-1\ge0\Leftrightarrow x\ge1\)
\(\left|x-1\right|=x-1\)
\(\Rightarrow x-1=1-x\)
\(\Leftrightarrow x+x=1+1\)
\(\Leftrightarrow2x=2\)
\(\Leftrightarrow x=1\left(TMDK\right)\)
* \(x-1< 0\Leftrightarrow x< 1\)
\(\left|x-1\right|=-\left(x-1\right)=1-x\)
\(\Rightarrow1-x=1-x\)
\(\Leftrightarrow-x+x=1-1\)
\(\Leftrightarrow0x=0\left(KTMDK\right)\)
Vậy \(x=1\)
a) \(\left|x-1\right|=1-x\)
*Nếu \(x-1\ge0\Rightarrow x\ge1\)
\(x-1=1-x\)
\(x+x=1+1\)
\(2x=2\)
\(x=1\)(thỏa mãn ĐK)
*Nếu \(x-1< 0\Rightarrow x< 1\)
\(-\left(x-1\right)=1-x\)
\(1-x=1-x\)
\(-x+x=1-1\)
\(0x=0\)
\(x\in R\)(trừ ĐK x < 1
