Question

Tìm x biết

a) \(\sqrt{x}\) = 4

b) \(\sqrt{x+1}\)= 5

c) \((x+1)^2=1\)

Answer 1

a\(\sqrt{x}=4\) => \(x=4^2\)=16

b \(\sqrt{x+1}=5\) thì \(x+1=5^2\)=25 hay x=24

c \(\left(x+1\right)^2=1\) =>\(\left(x+1\right)=1\) hay x=0

Cho mình 1 đúng đi

Answer 2

\(\sqrt{x}\)=4 => x= \(\left(\sqrt{4^{ }}\right)\)^2=4^2=16

\(\sqrt{x+1}\)=5 => \(\left(\sqrt{x+1}\right)\)^2=25

<=> x+1=25 => x=24

(x+1)^2= 1

TH1: x\(\ge\)0 => x+1=1 <=> x=0

TH2: x<o => x+1=-1 <=> x=-2

Answer 3

a)x=16

b)x=24

c)x=\(\sqrt{1}\) -1