b: 2x-3<0
=>2x<3
hay x<3/2
c: \(\left(2x-4\right)\left(9-3x\right)>0\)
=>(x-2)(x-3)<0
=>2<x<3
d: \(\dfrac{2}{3}x-\dfrac{3}{4}>0\)
=>2/3x>3/4
hay x>9/8
1. Tìm x:
a. |x| = 5,6 b. |x-3,5| = 5 c.|x+\(\dfrac{3}{4}\)| - \(\dfrac{1}{2}\)= 0 d. |4x| -|-13,5| = |\(\dfrac{9}{4}\)|
e. (x-1)3 = 27 f. (2x-3)2=36 g. 5x + 2= 625 h. (2x -1) 3 = -8
i.* \(\dfrac{1}{4}\).\(\dfrac{2}{6}.\dfrac{3}{8}.\dfrac{4}{10}.\dfrac{5}{12}...\dfrac{30}{62}.\dfrac{31}{64}=2^x\)
Tìm các số hữu tỷ x,biết rằng:
a,\(\left(x-\dfrac{5}{3}\right):-1\dfrac{3}{4}=0\)
b,\(\left(x-\dfrac{1}{5}\right)\left(1\dfrac{3}{5}+2x\right)=0\)
c,\(\left(x-\dfrac{4}{7}\right):\left(x+\dfrac{1}{2}\right)>0\)
d,(2x-3):\(\left(x+1\dfrac{3}{4}\right)< 0\)
Tìm x biết :
a)\(\dfrac{x+1}{2x+1}=\dfrac{\dfrac{1}{2}x+2}{x+3}\)
b) \(x^2+5x=0\)
c)\(\dfrac{1}{4}.\dfrac{2}{6}.\dfrac{3}{8}.\dfrac{4}{10}.\dfrac{5}{12}...\dfrac{30}{62}.\dfrac{31}{64}=2^x\)
tim
\(\dfrac{31-2x}{x+23}=\dfrac{9}{4}\),a
b,\(\dfrac{\left|2x-1\right|}{\dfrac{1}{2}}=\dfrac{18}{5}\)
c, \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
d, \(\dfrac{3x+2}{5x-3}=\dfrac{3x-1}{5x-3}\)
Tìm x, biết :
a) ( 2 - x ) . ( \(\dfrac{4}{5}\) - x ) < 0
b) ( x - \(\dfrac{1}{5}\)) . ( 1\(\dfrac{3}{5}\) + 2x ) = 0
Tìm x, biết:
a) ( 2 - x ) . ( \(\dfrac{4}{5}\)- x ) < 0
b) ( x - \(\dfrac{1}{5}\)) . ( 1 \(\dfrac{3}{5}\) + 2x ) = 0
tìm x biết
a.\(\left|x\right|-\dfrac{3}{4}=0\)
b. \(\dfrac{3}{4}+\dfrac{2x}{5}=\dfrac{29}{60}\)
Tinh x:
a)\(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
b)\(\dfrac{1}{4}+\dfrac{1}{3}:2x=-5\)
c)\(-2+\left|x+\dfrac{1}{5}\right|=\dfrac{9}{10}\)
Bài 1 Tìm x, y, z
a)\(\dfrac{y+z+1}{x}=\dfrac{x+z+2}{y}=\dfrac{x+y-3}{z}=\dfrac{1}{x+y+z}\)
b)\(\dfrac{2x}{3}=\dfrac{3y}{4}=\dfrac{4z}{5}\)và x+y+z=49
c)\(\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-4}{4}\) và 2x+3y-z=50
d)\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{5}\) và xyz=810
Giải cụ thể giúp mình nhé!!!
