Question

Tìm \(x\), biết :

a) \(\dfrac{1}{4}+x=-\dfrac{1}{3}\)

b) \(-\dfrac{3}{7}+x=\dfrac{5}{8}\)

c) \(0,472-x=1,634\)

d) \(-2,12-x=1\dfrac{3}{4}\)

Answer 1

a) \(\dfrac{1}{4}\) + x = \(-\dfrac{1}{3}\)

x = \(\dfrac{1}{4}\) + \(-\dfrac{1}{3}\)

x = \(\dfrac{-1}{12}\)

Vậy x = \(\dfrac{-1}{12}\)

b)\(-\dfrac{3}{7}+x=\dfrac{5}{8}\)

x = \(-\dfrac{3}{7}+\dfrac{5}{8}\)

x = \(\dfrac{11}{56}\)

Vậy x = \(\dfrac{11}{56}\)

c) 0,472 − x = 1,634

x = 0,472 − 1,634

x = -1,162

Vậy x = -1,162

d) −2,12 − x = \(1\dfrac{3}{4}\)

x = −2,12 − \(1\dfrac{3}{4}\)

x = -3,87

Vậy x = -3,87