a) \(3,6-\left|x-0,4\right|=0\)
=> \(\left|x-0,4\right|=3,6\)
=> \(x-0,4=\pm3,6\)
=> \(x=\left\{4;-3,2\right\}\)
b) \(\left|x-3,5\right|=7,5\)
=> \(x-3,5=\pm7,5\)
=> \(x=\left\{11;-4\right\}\)
Giải:
a) \(3,6-\left|x-0,4\right|=0\)
\(\Leftrightarrow\left|x-0,4\right|=3,6\)
\(\Leftrightarrow\left[{}\begin{matrix}x-0,4=3,6\\x-0,4=-3,6\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-3,2\end{matrix}\right.\)
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b) \(\left|x-3,5\right|=7,5\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3,5=7,5\\x-3,5=-7,5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=11\\x=-4\end{matrix}\right.\)
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