5\(^{x^2}\) -7x = 0-2
5\(^{x^2}\) -7x = -2
5x.x-7x = -2
(5x-7x).x = -2
-2x.x = -2
x.x = -2 : -2
\(^{x^2}\) = 1
=> \(^{x^2}\) = \(^{1^2}\) hoặc \(^{x^2}\) = \(^{\left(-1^{ }\right)^2}\)
=> x= 1 hoặc x = -1
Tìm x, biết:
5x2 - 7x + 2 = 0
=> 5x2 - 7x = 0 - 2
=> (5x - 7) . x = -2
=> -2x . x = -2
=> x . x = -2 : -2
=> x2 = 1
=> x = 1; -1
Vậy x là 1; -1
\(5x^2-7x+2=0\)
\(5x^2-7x=0+2\)
\(\left(5x.5x\right)-7x=2\)
\(25x-7x=2\)
\(18x=2\)
\(x=2:18=\frac{2}{18}\)
