\(2x.\left(x+\dfrac{1}{7}\right)=0\)
\(\Rightarrow\left\{{}\begin{matrix}2x=0\\x+\dfrac{1}{7}=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0\\x=\dfrac{-1}{7}\end{matrix}\right.\)
Vậy \(x\in\left\{\dfrac{-1}{7};0\right\}\)
Chúc bạn học tốt!!!
\(2x\left(x+\dfrac{1}{7}\right)=0\)
\(\Leftrightarrow2x=0\Rightarrow x=0\)
\(\Leftrightarrow x+\dfrac{1}{7}=0\Rightarrow x=-\dfrac{1}{7}\)