\(a,\)
\(2x.\left(x^2-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x=0\\x^2-4=0\end{matrix}\right.\left[{}\begin{matrix}x=0\\x^2=4\end{matrix}\right.\left[{}\begin{matrix}x=0\\x=\pm2\end{matrix}\right.\)
Vậy \(x\in\left\{0;2;-2\right\}\)
2x(x2-4)=0
<=> 2x(x - 2)(x + 2)=0
2x=0 x=0
⇔ x-2=0 ⇔ x=2
x+2=0 x=-2
do ko bt làm dấu như bn lana nên bn thông cảm