a,\(\left(5x-1\right)^6=729\)
\(\left(5x-1\right)^6=3^6\)
\(5x-1=3\)
\(5x=4\)
\(x=\dfrac{4}{5}\)
b Ta có \(8=2^3\),\(25=5^2\)
Mà \(\dfrac{8}{25}=\dfrac{2^x}{5^{x-1}}\)
=> \(2^3=2^x,5^2=5^{x-1}\)
=> x=3
c Ta có \(16=2^4\)
hay \(\left(\dfrac{1}{2^4}\right)^x=\left(\dfrac{1}{2}\right)^{10}=>x\cdot4=10=>x=\dfrac{10}{4}=\dfrac{5}{2}\)
d \(9^x:3^x=3=>3^{2\cdot x}:3^x=3=>2\cdot x-x=1=>x=1\)