b) 2x(x - 2012) - x + 2012 = 0
<=> 2x(x - 2012) - (x - 2012)= 0
<=> (x - 2012)(2x - 1) = 0
<=> \(\begin{bmatrix} x - 2012= 0 & & \\ 2x - 1 = 0 & & \end{bmatrix} \)
<=> \(\begin{bmatrix} x = 2012 & & \\ x = \frac{1}{2} & & \end{bmatrix} \)
Vậy x = 2012 và x= \(\frac{1}{2}\)
pn bỏ dấu ngoặc vuông bên phải nhé
Tìm x biết:
a) (2x - 3).(x + 5) = 0
b) 3x.(x - 2) - 7.(x - 2) = 0
c) 5x.(2x - 3) - 6x + 9 = 0
Tìm x biết a) x(x-25)=0 b)2x(x-4)-x(2x-1)=-28 c)x^2 -5x=0 d)(x-2)^2-(x+1)(x+3)=-7 e)(3x+5).(4-3x)=0 f)x^2-1/4=0
1. Tìm x:
a) x2 - 3x = 0
b) 2x ( x - 2 ) - (x - 2 ) = 0
c) x + 5x2 = 0
d) x + 1 = ( x + 1 )2
e) x3 + x = 0
f) 5 ( x + 3 ) - 2x ( 3 + x ) = 0
h) 6x ( x2 - 2 ) - ( 2 - x2 ) = 0
i) ( x + 1 )2 - ( x + 1 ) ( x - 2 ) = 0
Tìm x biết:
a) 7x.(2x - 3) - (4x2 - 9) = 0
b) (2x - 7).(x - 2).(x2 - 4) = 0
c) (9x2 - 25) - (6x - 10) = 0
1. Tìm x biết:
a) x2-2x-3=0
b)2x2+5x-2=0
c)x3+3x2-4=0
d)x3+x2-2=0
2. Phân tích đa thức sau thành nhân tử:
a)x2-6x+8
b)9x2-6x-8
c) x2-7x+12
d)x2-5x-14
e)4x2-3x-1
tim x
(2x-3)(x+1)+(2x-3)(3x-7)=0
(x-4)(3x-2)+x^2-16=0
1. Phân tích...nhân tử:
a) 2a ( x - y ) - ( y - x )
b) a2 ( x - y ) - ( y - x )
c) x ( x - y ) + y ( y - x ) - 3 ( x - y )
d) 6x2 - 3 + 7x ( 6x2 - 3 ) + 4y ( 3 - 6x2 )
2. Tìm x:
a) x2 + 2x = 0
b) x ( x - 5 ) = 5 - x
c) ( x + 1 ) ( 6x2 + 2x ) + ( x - 1 ) ( 6x2 + 2x ) = 0
Tìm x:
a) 5x2(2x-3)+(2x2+3x+3)(3-2x)=6x3-9x2
b) (4x2+2x)(x2-x)+(4x2+6)(x-x2)=0
2. Tìm x, biết:
a) 2x2 + 3x = 0
b) (2x + 1)(x-2) - 5(1-2x) = 0
c) x2 = (2x -1)2
d) 4x3 - x = 0
