a) \(4x^2-12x+9-4\left(x^2-4\right)-x=8\)
\(4x^2-12x+9-4x^2+16-x=8\)
\(-13x+25=8\)
\(-13x=-17\)
\(x=\dfrac{17}{13}\)
b) \(\left(3x^3+6x^2\right):3x^2+\left(9x^2-6x\right):0,5x=9\)
\(x+2+18x-12=9\)
\(19x-10=9\)
\(19x=19\)
\(x=1\)
a) (2x - 3)2 - 4(x + 2)(x - 2) - x = 8
4x2 - 12x + 9 - 4(x2 - 4) - x = 8
4x2 - 12x + 9 - 4x2 + 16 - x = 8
-13x + 25 = 8
\(\Rightarrow\) -13x = -17
\(\Rightarrow\) x = \(\dfrac{17}{13}\)
b) (3x3 + 6x2) : 3x2 + (9x2 - 6x) : 0,5x = 9
3x2(x + 2) : 3x2 + 3x(3x - 2) : 0,5x = 9
\(\Rightarrow\) x + 2 + 6.(3x - 2) = 9
\(\Rightarrow\) x + 2 + 18x - 12 = 9
\(\Rightarrow\) 19x - 10 = 9
\(\Rightarrow\) 19x = 19
\(\Rightarrow\) x = 1
chúc bn học tốt. nhớ tik mik nhé 
a) \((2x - 3 )^2 - 4(x+2) (x - 2) - x = 8\)
\(\Rightarrow\) \(4x^2 - 12x + 9 - 4(x^2 - 4 ) -x = 8\)
\(\Rightarrow\) \(4x^2 - 12x + 9 - 4x^2 + 16 - x = 8\)
\(\Rightarrow\) \(- 13x + 25 = 8\)
\(\Rightarrow\) \(- 13x = -17\)
\(\Rightarrow\) \(x=\dfrac{17}{13}\)
b) \((3x^3 + 6x^2) : 3x^2 + (9x^2 - 6x ) 0,5x = 9\)
\(\Rightarrow\) \(3x^2(x+2) : 3x^2 + 3x(3x - 2) : 0,5x = 9\)
\(\Rightarrow x+2+6.\left(3x-2\right)=9\)
\(\Rightarrow x+2+18x-12=9\)
\(\Rightarrow\) \(19x - 10 = 9\)
\(\Rightarrow\) \(19x = 19\)
\(\Rightarrow x=1\)
HỌC TỐt NHA BẠN !!!