Sửa đề:\(4^{x+3}-3\cdot4^{x+1}=13\cdot4^{11}\)
\(\Leftrightarrow4^x\cdot64-3\cdot4^x\cdot4=13\cdot4^{11}\)
\(\Leftrightarrow4^x\cdot52=52\cdot4^{10}\)
\(\Leftrightarrow4^x=4^{10}\)
hay x=10
Sửa đề:\(4^{x+3}-3\cdot4^{x+1}=13\cdot4^{11}\)
\(\Leftrightarrow4^x\cdot64-3\cdot4^x\cdot4=13\cdot4^{11}\)
\(\Leftrightarrow4^x\cdot52=52\cdot4^{10}\)
\(\Leftrightarrow4^x=4^{10}\)
hay x=10
4x+3 - 3.4x+1 = 13.411
Tìm x :
\(4^{x+3}-3.4^{x+1}=13.4^{11}\)
Tìm x
4x+3-3.4x+1=13.411
bài 6 : tìm x :
câu 9, \(3^x=9^{-6}.27^{-5}.81^8\)
câu 18, \(4^{x+3}-3.4^{x+1}=13.4^{11}\)
Tìm x biết |2x - 3 |x - 1| | = 11
Bài 2 Tìm x biết :
a) -5 | x - 3 | + | 1/2x + 4 | = 7|
b) | 2x + 1 | - 4 | 5 - x | = 9
c) | 9 - | x | = 8
d) - | 2x + 4/3 | - 11 - x | = -7/3
1) Giá trị \(x\in Z\) để \(\frac{x-5}{7-x}\) là số hữu tỉ dương. x = ?
2) Cặp số nguyên dương chẵn x; y thỏa mãn biểu thức \(\frac{x}{2}+\frac{3}{7}=\frac{5}{4}\). Vậy x = .... ; y = ....
3) Giá trị \(A=\frac{\frac{2}{5}+\frac{2}{7}-\frac{2}{11}}{\frac{3}{5}+\frac{3}{7}-\frac{3}{11}}+\frac{\frac{1}{4}-\frac{1}{5}+\frac{1}{7}}{\frac{3}{4}-\frac{3}{5}+\frac{3}{4}}\)
\(Tìm\) \(x,\) \(biết\) \(:\)
\(a)\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}+=\frac{x+1}{13}+\frac{x+1}{14}\\ b)\frac{x+4}{2000}+\frac{x+3}{2001}=\frac{x+2}{2002}+\frac{x+1}{2003}\)
tìm x
a, x+1/10 + x+1/11 + x+1/12 = x+1/13 + x+1/14
b, x+4/2000 + x+3/2001 = x+2/2002 + x+1/2003