Question

tìm x: 4/5 + 1/5 . x/3 = 9

Answer 1

4/5+1/5.x/3=9

1/5.x/3=9-4/5

1/5.x/3=41/5

x/3=41/5:1/5

x/3=41

x=123

Answer 2

\(\dfrac{4}{5}+\dfrac{1}{5}.\dfrac{x}{3}=9\)

\(\dfrac{1}{5}.\dfrac{x}{3}=9-\dfrac{4}{5}\)

\(\dfrac{1}{5}.\dfrac{x}{3}=\dfrac{41}{5}\)

\(\dfrac{x}{3}=\dfrac{41}{5}:\dfrac{1}{5}\)

\(\dfrac{x}{3}=41\)

\(x=123\)

Answer 3

\(\dfrac{4}{5}+\dfrac{1}{5}.\dfrac{x}{3}=9\) \(\Leftrightarrow\dfrac{1}{5}.\dfrac{x}{3}=9-\dfrac{4}{5}\) \(\Leftrightarrow\dfrac{1}{5}.\dfrac{x}{3}=\dfrac{41}{5}\)

\(\Leftrightarrow\dfrac{x}{3}=\dfrac{41}{5}:\dfrac{1}{5}\) \(\Leftrightarrow\dfrac{x}{3}=41\) \(\Leftrightarrow x=123\)

Answer 4

Bài 1 : Tìm x

\(\dfrac{4}{5}\) + \(\dfrac{1}{5}\) . \(\dfrac{x}{3}\) = 9

\(\dfrac{1}{5}.\dfrac{x}{3}=9-\dfrac{4}{5}\)

\(\dfrac{1}{5}.\dfrac{x}{3}\)= \(\dfrac{41}{5}\)

\(\dfrac{x}{3}\)= 41

x = 123

Vậy x = 123