Lời giải:
$3^{x-1}+4.3^{x-2}=\frac{7}{243}$
$\Leftrightarrow 3. 3^{x-2}+4.3^{x-2}=\frac{7}{243}$
$\Leftrightarrow 3^{x-2}(3+4)=\frac{7}{243}$
$\Rightarrow 3^{x-2}=\frac{1}{243}=3^{-5}$
$\Rightarrow x-2=-5$
$\Rightarrow x=-3$
\(3^{x-1}+4.3^{x-2}=\frac{7}{243}\)
\(\Rightarrow3^1.3^{x-2}+4.3^{x-2}=\frac{7}{243}\)
\(\Rightarrow3^{x-2}.\left(3^1+4\right)=\frac{7}{243}\)
\(\Rightarrow3^{x-2}.7=\frac{7}{243}\)
\(\Rightarrow3^{x-2}=\frac{7}{243}:7\)
\(\Rightarrow3^{x-2}=\frac{1}{243}\)
\(\Rightarrow3^{x-2}=3^{-5}\)
\(\Rightarrow x-2=-5\)
\(\Rightarrow x=\left(-5\right)+2\)
\(\Rightarrow x=-3\)
Vậy \(x=-3.\)
Chúc bạn học tốt!
