\(2x\left(x-\dfrac{1}{7}\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)
\(2x\left(x-\dfrac{1}{7}\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)
Vậy...
=> \(\left\{{}\begin{matrix}2x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)
Vậy giá trị cần tìm là x = 0 ; x = \(\dfrac{1}{7}\)
2x.(x-1/7)=0
=> 2x=0 hoặc x-1/7=0
*(1) 2x-1=0
=> 2x=1
=> x=1/2
*(2) x-1/7=0
=> x=0+1/7
=> x= 1/7
Vậy x=1/2 hoặc 1/7
phần 1 mk sai r
2x=0
=>x=0
Kết luận
Vậy x=0 hoặc 1/7
Chú ý:A.B=0 thì A=0 hoặc B=0.
\(2x.\left(x-\dfrac{1}{7}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)
Vậy \(x=0\) hoặc \(x=\dfrac{1}{7}\) .
