\((2x-1)^3=8\)
\(2x-1=2\)
\(2x=3\)
\(x=\dfrac{3}{2}\)
\(\left(2x-1\right)^3=-8\Leftrightarrow2x-1=\sqrt[3]{-8}\Leftrightarrow2x-1=-2\)
\(\Leftrightarrow2x=-2+1\Leftrightarrow2x=-1\Leftrightarrow x=\dfrac{-1}{2}\) vậy \(x=\dfrac{-1}{2}\)
\(\left(2x-1\right)^3=-8\)
\(\Leftrightarrow\left(2x-1\right)^3=\left(-2\right)^3\)
\(\Rightarrow2x-1=-2\)
\(2x=-1\)
\(x=-0,5\)
\(\left(2x-1\right)^3=-8\)
\(\Leftrightarrow\left(2x-1\right)^3=-2^3\)
\(\Leftrightarrow2x-1=-2\)
\(\Leftrightarrow2x=-1\)
\(\Leftrightarrow x=-\dfrac{1}{2}\)
Tìm x :
(2x - 1)3 = -8
(2x - 1)3 = (-2)3
2x - 1 = -2
2x = -1
x = \(\dfrac{-1}{2}\)
hay x = 0,5
Vậy x = 0,5
\(\left(2x-1\right)^3=-8\)
\(\left(2x-1\right)^3=-2\)
\(\left(2x-1\right)=-2^3\)
\(\left(2x-1\right)=-2\)
\(2x=-1\)
\(x=-1:2\)
\(x=\dfrac{-1}{2}\)
