\(2\left|2x+3\right|-3=5-x\)
\(\Leftrightarrow2.\left|x+3\right|=5+3-x\)
\(\Leftrightarrow2.\left|x+3\right|+x=8\)
\(\Leftrightarrow2.\left|x+3\right|\ge0;8>0\Rightarrow x>0\)
\(\Leftrightarrow2x+6+x=8\)
\(\Leftrightarrow3x=14\)
\(\Leftrightarrow x=\frac{14}{3}\)
2|2x+3|-3=5-x
TH1:2.(2x+3)-3=5-x
4x+6-3=5-x
4x+3=5-x
4x+x=5-3
5x=2
x=\(\frac{2}{5}\)
TH2: 2.-(2x+3)-3=5-x
2.(-2x-3)-3=5-x
-4x-6-3=5-x
-4x-9=5-x
-4x+x=5+9
-3x=14
x=\(-\frac{14}{3}\)
Vậy x=\(\frac{2}{5}\);x=\(-\frac{14}{3}\)