=>|x-3/2|=3/4-1/6=9/12-2/12=7/12
=>x-3/2=7/12 hoặc x-3/2=-7/12
=>x=25/12 hoặc x=11/12
\(1,\dfrac{3}{4}-\left|x-\dfrac{3}{2}\right|=\dfrac{1}{6}\)
\(\Rightarrow\left|x-\dfrac{3}{2}\right|=\dfrac{3}{4}-\dfrac{1}{6}\)
\(\Rightarrow\left|x-\dfrac{3}{2}\right|=\dfrac{9}{12}-\dfrac{2}{12}\)
\(\Rightarrow\left|x-\dfrac{3}{2}\right|=\dfrac{7}{12}\)
\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{3}{2}=\dfrac{7}{12}\\x-\dfrac{3}{2}=\dfrac{-7}{12}\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{25}{12}\\x=\dfrac{11}{12}\end{matrix}\right.\)
Vậy \(x\in\left\{\dfrac{25}{12};\dfrac{11}{12}\right\}\)
