\(1+2\left(x-1\right)\left(x+2\right)-2\left(2x-1\right)^2=3-4\left(2x+3\right)-3\left(x+1\right)\)
<=> \(1+2\left(x^2+x-2\right)-2\left(4x^2-4x+1\right)=3-8x-12-3x-1\)
<=>\(1+2x^2+2x-4-8x^2+8x-2-3+8x+12+3x+1=0\)
<=> \(-6x^2+5x+5=0\)
<=> \(\left[\begin{array}{nghiempt}x=\frac{5+\sqrt{145}}{12}\\x=\frac{5-\sqrt{145}}{12}\end{array}\right.\)
hai nghiệm trên là nghiệm của pt